Victoria Azarenka woke up just in time on Monday, rallying for a 3-6, 6-3, 6-0 victory over Belgian Kirsten Flipkens that kept her Indian Wells WTA title defence on track.
Azarenka remained unbeaten in 2013, having successfully defended her Australian Open title and her WTA Doha crown.
The 23-year-old from Belarus, currently ranked second in the world behind American Serena Williams, is vying to become the first woman to win back-to-back titles at Indian Wells since Martina Navratilova in 1990 and 1991.
But she showed far from dominant form in a scrappy first set against Flipkens, a 27-year-old ranked 31 in the world.
After she’d held her serve to open the second set she and Flipkens exchanged breaks in the next four games before Azarenka earned the decisive break in the eighth.
She served it out with a love game and a demoralized Flipkens had no answer in the third.
Azarenka, who next faces unseeded Urszula Radwanska of Poland, led a parade of the top 10 seeds into the women’s round of 16 scheduled for Tuesday.
Second-seeded Maria Sharapova, No. 3 Agnieszka Radwanska and fifth-seeded Petra Kvitova had advanced on Sunday.
No. 4 Angelique Kerber of German advanced on Monday with a 6-1, 7-6 (7/4) victory over Belgian Yanina Wickmayer.
Seventh-seeded Australian Sam Stosur, a former US Open champion, defeated China’s Peng Shuai 6-3, 3-6, 6-2 and eighth-seeded Caroline Wozniacki breezed past Russian Elena Vesnina 6-2, 6-1.
Kerber had to dig deep in the second set but said words of encouragement from her coach when she trailed 4-1 helped her turn it around. (AFP)